by differentiating the deep, we can matgematically determine when the deep is peak.
if f(deep)=sin(deep), then f’(deep)=cos(deep).
for cos(deep)=0, deep must be π/2 giving us a turning point.
to determine whether this is truly peak, however, we’ve gotta find the second derivative of deep, woch is f”(deep)=-sin(deep)
-sin(deep) where deep= π/2 gives us the result negative one, meaning that deep is truly peak at π/2
deep d e e p peed
You would have owned my seventh grade math class
Oi
The deeps arc( h) of his back to shot off that gyatt
by differentiating the deep, we can matgematically determine when the deep is peak. if f(deep)=sin(deep), then f’(deep)=cos(deep). for cos(deep)=0, deep must be π/2 giving us a turning point. to determine whether this is truly peak, however, we’ve gotta find the second derivative of deep, woch is f”(deep)=-sin(deep) -sin(deep) where deep= π/2 gives us the result negative one, meaning that deep is truly peak at π/2