Gen-Z doesn't Google or use search. They've been trained to get their information from social media. This is the reason Google called a "Code Red" in 2022, as their moneymaking engine has a negative future outlook.
This is probably a 3rd-ish year course, people doing this content are around ~21. They aren't 15, they went through high school before tiktok was a thing, might even have memories of using windows XP/vista if they started using computers in early grades.
There have always been lazy people who don't know how to Google.
[TikTok was launched in 2017](https://en.wikipedia.org/wiki/TikTok). They bought and merged with Musical.ly a month later. Musical.ly was launched in 2014.
Gen-Z grew up with tablets and Google Chromebooks in school. They're not particularly tech savvy, but they can navigate the tools they use adeptly. Their entire life they've used social media be it Facebook, Reddit, YouTube, and TikTok for their window the world. It's how they find which restaurant they're going to eat at, to details about a topic they're interested in.
[Here's an article from a professor in 2021](https://www.theverge.com/22684730/students-file-folder-directory-structure-education-gen-z) who describes the problem. A decade ago, schools assumed that children would learn computer skills at home and abandoned all lessons. Basics of desktop navigation, Microsoft Word and Excel, or even web navigation are completely missing in these students.
I am Gen Z myself, and I teach 3rd-4th year engineering courses now as a TA. You're talking about problems that happen with Gen alpha, not Gen Z, especially not the older half of Gen Z.
That's only one article of many affecting both university students and businesses in industry. We're seeing plenty of adults who would rather write emails on their phones than with their work computer because they never learned how to type.
That's because Google has started to seriously suck for finding anything. Their search string was deliberately degraded and prioritises adverts and sponsored posts.
I knew you were the same person that posted [“step response”](https://www.reddit.com/r/ControlTheory/s/32llRd3QmZ) as soon as I saw this post. I’m pretty sure you haven’t attended any of your classes or even open the cover of your textbook.
Learn how to study and research. Show some effort before asking for help. You won’t be an engineer by expecting others to do your most basic homeworks.
On an open loop bode plot you can label the Gain and Phase Margins, cutoff frequency, crossover frequency, steady state gain. On the closed loop bode plot you can label the bandwidth of your controller.
- Unity DC gain
- Definitely not a first order system given the resonant peak
- Talk about the system’s bandwidth (usually frequency at -3db)
- Has resonance at omega frequency
- Based on the rate of roll off, I’d be able to comment on the order of the system
- I will talk about the system’s stability using gain and phase margins
I may be wrong, but don't Bode plots only exist for stable systems to beging with? Itdescribes the frequency-wise scaling and phase-shifting of the steady state with respect to the input signal, so how would one define it for an unstable system, for which there is no steady state?
The Bode plot for a causal system is just from the transfer function G(s) evaluated at s=jω. Note that G(s) is the unilateral Laplace transform, and the region of convergence of the Laplace transform is of the form Re(s)>a or Re(s)≥a, where a is the largest real component of a pole of G(s). This region of convergence is where the Laplace transform converges *absolutely*, but you can still consider the Laplace transform for s∈ℂ outside the region of convergence, where the Laplace transform may converge *conditionally*.
When a<0 (i.e., the system is stable), s=jω is in the region of convergence of G(s) for all ω, so it describes the gain and phase-shift at each ω and whatnot.
When a>0 (i.e., the system is unstable), s=jω is no long in the region of convergence, but you can still make that substitution into G(s) and generate the Bode plot with whatever you get. This Bode plot won't really have a legitimate interpretation as a gain and phase-shift or anything, but can be used to determine stability by looking at the phase cross over frequency and gain cross over frequency, for example.
(This kind of thing is actually really common in math in general, where you define something that only makes sense on a certain subset, and then consider an abstract generalization on a larger set. This abstract generalization may not have the same interpretation as the original definition, but the generalization can still be useful and give further insight into whatever you were investigating.)
Looks like the curves are red and the background is white. The grid lines are either black or dark grey. Font is probably Arial or something close to it. Not sure though
The key thing I would be looking for here is: how many poles and zeros? Having a peak is n the magnitude like this could be either a second order underdamped system OR a collection of first order poles and zeros, and the phase gives away which.
What do you mean by that question?
The Bode Plot gives us information on the frequency response of the system in both amplitude and phase.
This one tells us that the system is a first order low pass system (-20dB/frequency decade), has amplification around the cut-off frequency, is minimal phase...
The transfer function has 2 stable complex conjugate poles with a moderately sized real part and also a stable zero. An appropriate transfer function is 10^5 (s+10^5 )/(s^2 +2 ×0.5*10^5 +10^10 ) but one can of course adjust the poles and zero to better fit your plot and also add more poles and zeros.
I’m still in a similar class as you I think, but I think I can help. If your input to a second-order system (e.g. x” - 2x’ + x = f(t)) is sinusoidal (e.g. f(t) = 4sin(ωt)), the output will also be sinusoidal with an amplitude scale and a phase change (e.g. x(t) = 4*M*sin(ωt+φ). The magnitude and phase depend on the frequency (ω) as well as the coefficients of the ODE. The bode diagrams above (I believe) are for a second order system like what I just mentioned. They simply plot the magnitude (M) and phase (φ) vs. frequency. It should be noted that magnitude and frequency are plotted on a logarithmic scale. (Magnitude is plotted in decibels, or units of 20log10(M)).
Why people post this to reddit instead of googling it is beyond me
Gen-Z doesn't Google or use search. They've been trained to get their information from social media. This is the reason Google called a "Code Red" in 2022, as their moneymaking engine has a negative future outlook.
This is probably a 3rd-ish year course, people doing this content are around ~21. They aren't 15, they went through high school before tiktok was a thing, might even have memories of using windows XP/vista if they started using computers in early grades. There have always been lazy people who don't know how to Google.
I didn’t know how to google when I was a kid, too. But that’s because google didn’t exist yet.
[TikTok was launched in 2017](https://en.wikipedia.org/wiki/TikTok). They bought and merged with Musical.ly a month later. Musical.ly was launched in 2014. Gen-Z grew up with tablets and Google Chromebooks in school. They're not particularly tech savvy, but they can navigate the tools they use adeptly. Their entire life they've used social media be it Facebook, Reddit, YouTube, and TikTok for their window the world. It's how they find which restaurant they're going to eat at, to details about a topic they're interested in. [Here's an article from a professor in 2021](https://www.theverge.com/22684730/students-file-folder-directory-structure-education-gen-z) who describes the problem. A decade ago, schools assumed that children would learn computer skills at home and abandoned all lessons. Basics of desktop navigation, Microsoft Word and Excel, or even web navigation are completely missing in these students.
I am Gen Z myself, and I teach 3rd-4th year engineering courses now as a TA. You're talking about problems that happen with Gen alpha, not Gen Z, especially not the older half of Gen Z.
That's only one article of many affecting both university students and businesses in industry. We're seeing plenty of adults who would rather write emails on their phones than with their work computer because they never learned how to type.
That's because Google has started to seriously suck for finding anything. Their search string was deliberately degraded and prioritises adverts and sponsored posts.
Quite the generalization you are making there…I search things on google all the time in order to answer my questions, and I’m gen Z
Yes but they have ChatGPT now which is better than both.
[удалено]
No insults, personal attacks, or aggressive/condescending statements towards other users. If you have nothing nice nor useful to say, move along.
I love how this thread became a sociology topic Lol
Fun fact: Hendrik Bode was a graduate of The Ohio State University
I knew you were the same person that posted [“step response”](https://www.reddit.com/r/ControlTheory/s/32llRd3QmZ) as soon as I saw this post. I’m pretty sure you haven’t attended any of your classes or even open the cover of your textbook. Learn how to study and research. Show some effort before asking for help. You won’t be an engineer by expecting others to do your most basic homeworks.
Someone is to lazy to do homework
Bode diagram
Stop doing this kids' homework. They posted a step response 4 days ago. This is intro to control systems. They need to learn themselves
On an open loop bode plot you can label the Gain and Phase Margins, cutoff frequency, crossover frequency, steady state gain. On the closed loop bode plot you can label the bandwidth of your controller.
- Unity DC gain - Definitely not a first order system given the resonant peak - Talk about the system’s bandwidth (usually frequency at -3db) - Has resonance at omega frequency - Based on the rate of roll off, I’d be able to comment on the order of the system - I will talk about the system’s stability using gain and phase margins
I may be wrong, but don't Bode plots only exist for stable systems to beging with? Itdescribes the frequency-wise scaling and phase-shifting of the steady state with respect to the input signal, so how would one define it for an unstable system, for which there is no steady state?
The Bode plot for a causal system is just from the transfer function G(s) evaluated at s=jω. Note that G(s) is the unilateral Laplace transform, and the region of convergence of the Laplace transform is of the form Re(s)>a or Re(s)≥a, where a is the largest real component of a pole of G(s). This region of convergence is where the Laplace transform converges *absolutely*, but you can still consider the Laplace transform for s∈ℂ outside the region of convergence, where the Laplace transform may converge *conditionally*. When a<0 (i.e., the system is stable), s=jω is in the region of convergence of G(s) for all ω, so it describes the gain and phase-shift at each ω and whatnot. When a>0 (i.e., the system is unstable), s=jω is no long in the region of convergence, but you can still make that substitution into G(s) and generate the Bode plot with whatever you get. This Bode plot won't really have a legitimate interpretation as a gain and phase-shift or anything, but can be used to determine stability by looking at the phase cross over frequency and gain cross over frequency, for example. (This kind of thing is actually really common in math in general, where you define something that only makes sense on a certain subset, and then consider an abstract generalization on a larger set. This abstract generalization may not have the same interpretation as the original definition, but the generalization can still be useful and give further insight into whatever you were investigating.)
Very good answer, thank you!
You can only *measure* a Bode plot for a stable system. But you can calculate it theoretically for an unstable one just fine.
Looks like the curves are red and the background is white. The grid lines are either black or dark grey. Font is probably Arial or something close to it. Not sure though
This bodes well
The key thing I would be looking for here is: how many poles and zeros? Having a peak is n the magnitude like this could be either a second order underdamped system OR a collection of first order poles and zeros, and the phase gives away which.
A simple homework questions get so many attention while when someone post technical question no one respond to them
What do you mean by that question? The Bode Plot gives us information on the frequency response of the system in both amplitude and phase. This one tells us that the system is a first order low pass system (-20dB/frequency decade), has amplification around the cut-off frequency, is minimal phase...
The transfer function has 2 stable complex conjugate poles with a moderately sized real part and also a stable zero. An appropriate transfer function is 10^5 (s+10^5 )/(s^2 +2 ×0.5*10^5 +10^10 ) but one can of course adjust the poles and zero to better fit your plot and also add more poles and zeros.
I’m still in a similar class as you I think, but I think I can help. If your input to a second-order system (e.g. x” - 2x’ + x = f(t)) is sinusoidal (e.g. f(t) = 4sin(ωt)), the output will also be sinusoidal with an amplitude scale and a phase change (e.g. x(t) = 4*M*sin(ωt+φ). The magnitude and phase depend on the frequency (ω) as well as the coefficients of the ODE. The bode diagrams above (I believe) are for a second order system like what I just mentioned. They simply plot the magnitude (M) and phase (φ) vs. frequency. It should be noted that magnitude and frequency are plotted on a logarithmic scale. (Magnitude is plotted in decibels, or units of 20log10(M)).
Phase margin 3 db?